hnagoya

  When $a\ne 0$, there are two solutions to $a{x}^2+bx+c=0$ and they are   $$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}.$$ テーマ編集の参考記事 https://hidehikomurao.blogspot.com/2019/04/bloggermathjax.html