hnagoya

  When \(a \ne 0\), there are two solutions to \(ax^2 + bx + c = 0\) and they are   \[x = {-b \pm \sqrt{b^2-4ac} \over 2a}.\] テーマ編集の参考記事 https://hidehikomurao.blogspot.com/2019/04/bloggermathjax.html